Applied-Algebra Exam Preparation Material | WGU Applied Algebra FXO2 PFXP C957

Explanation:
The function represents the company’s predicted market share after years.
The horizontal axis represents:
The vertical axis represents:
We need to find when the company’s market share reaches:
To answer this from the graph:
Locate on the vertical axis.
Move horizontally until reaching the blue curve.
Move downward to the horizontal axis to read the corresponding time.
From the graph, the blue curve reaches a little after years, approximately at:
So the company should expect to have a market share of after about:

Explanation:
We are told that computer B completes 12 more tasks than computer A.
Let:
and
The phrase “12 more than” means add 12 to the original amount:
So, if computer A completes tasks, computer B completes:
tasks.
For example, if computer A completed 50 tasks, then computer B completed:
Therefore, the correct answer is:

Explanation:
The function represents the number of people expected to audition this year.
The input represents the number of people who auditioned last year.
The problem says this year’s number is expected to be 3 less than last year’s number. Therefore, the function rule is:
We are told that 280 people auditioned last year, so:
Substitute into the function:
So, the notation that represents the number of people expected to audition this year is:
This means if 280 people auditioned last year, then 277 people are expected to audition this year.
Therefore, the correct answer is:

Explanation:
From week 1 to week 7, the graph is increasing and becoming steeper.
In Applied Algebra, when a graph is increasing and its slope is getting larger, the quantity is said to be:
This interval is on the early increasing part of the logistic curve, before the graph begins to level off.
Therefore, the correct answer is:

Explanation:
This graph represents a logistic growth function, which has an S-shaped curve:
Slow growth at the beginning (near point A)
Rapid growth in the middle (near point B and C)
Slowing growth at the end (near point D)
Key Concept:
Instantaneous rate of change = slope of the tangent line at a single point
Average rate of change = slope between two points
Analyze the graph:
At point A → slope is small (slow increase)
From A to C → increasing but not maximum
At point C → curve is steepest → maximum slope
From C to D → curve flattens → smaller slope
At point D → slope is very small (almost flat)
Conclusion:
The greatest rate of change occurs where the graph is steepest, which is at: